Question

Escribir la formula y hallar la masa molecular. .propanona . 3-nonanona . 2-pentanona . 8-metil-2-decanona . Butanona . 3-metil-2-butanona . 5-hepten-3-ona . 4-pentino-2,3-diona

Answer 1

.propanona CH3 - C - CH3   C₃H₆O
                              ΙΙ
                              O
Mm de la propanona
C: 3 x 12 = 36 g/mol
H: 6 x 1 = 6 g/mol
O: 1 x 16 = 16 g/mol
```````````````````````````````
      Mm = 58 g/mol
                       
- 3-nonanona  C₉H₁₈O
₁          ₂        ₃     ₄         ₅         ₆         ₇         ₈         ₉
CH3 - CH2 - C - CH2 - CH2 - CH2 - CH2 - CH2 - CH3
                     ΙΙ
                    O
Mm
C: 9 x 12 = 108 g/mol
H: 18 x 1 = 18 g/mol
O: 1 x 16 = 16 g/mol
```````````````````````````````
          Mm = 142 g/mol

. 2-pentanona C₅H₁₀O

CH3 - C - CH2 - CH2 - CH3
           ΙΙ
           O
Mm
C: 5 x 12 = 60 g/mol
H: 10 x 1 = 10 g/mol
O: 1 x 16 = 16 g/mol
```````````````````````````````
          Mm = 86 g/mol

. 8-metil-2-decanona  
₁         ₂    ₃         ₄        ₅        ₆         ₇         ₈       ₉        ₁₀
CH₃ - C - CH₂ - CH₂ - CH₂ - CH₂ - CH₂ - CH - CH₂ - CH₃
          ΙΙ                                                    Ι
          O                                                   CH₃
Mm
C: 11 x 12 = 132 g/mol
H: 22 x 1 = 22 g/mol
O: 1 x 16 = 16 g/mol
``````````````````````````````
           Mm = 170 g/mol

. Butanona    C₄H₈O

CH₃ - C - CH₂ - CH₃
          ΙΙ
          O
Mm
C: 4 x 12 = 48 g/mol
H: 8 x 1 = 8 g/mol
O: 1 x 16 = 16 g/mol
``````````````````````````````
           Mm = 72 g/mol

. 3-metil-2-butanona

CH3 - C - CH - CH3
           ΙΙ   Ι
           O  CH₃
Mm
C: 5 x 12 = 60 g/mol
H: 10 x 1 = 10 g/mol
O: 1 x 16 = 16 g/mol
``````````````````````````````
         Mm = 86 g/mol

. 5-hepten-3-ona

₁          ₂         ₃    ₄         ₅        ₆       ₇
CH3 - CH2 - C - CH2 - CH = CH - CH3
                     ΙΙ
                     O
Mm
C: 7 x 12 = 84 g/mol
H: 12 x 1 = 12 g/mol
O: 1 x 16 = 16 g/mol
`````````````````````````````
         Mm = 112 g/mol

. 4-pentino-2,3-diona 
₁           ₂       ₃      ₄      ₅
CH3  -  C  -  C  -  C Ξ CH
            ΙΙ       ΙΙ
            O      O
Mm
C: 5  x  12 = 60 g/mol
H: 4  x  1 = 4 g/mol
O: 2 x 16 = 32 g/mol
```````````````````````````````
          Mm = 96 g/mol