Question

es urgente por favor :c

Answer 1

-6x² -x +1 > 0

-6(x - 1/3)(x + 1/2) > 0

6(1/3 - x)(x + 1/2) > 0

x + 1/2 > 0

x > -1/2

1/3 - x > 0

x < 1/3

Rta: 1/3 > x > -1/2

2x² +6x -9 < 0

x = (-3 ± √27)/2

2(x - (-3 - √27)/2)(x - (-3 + √27)/2) < 0

2(x + 3/2 + √27/2)(x + 3/2 - √27/2) < 0

-2(-x -3/2 -√27/2)(x + 3/2 - √27/2) < 0

X + 3/2 - √27/2 < 0

X < -(3 - √27)/2

-x - 3/2 - √27/2 < 0

x > -(3 + √27)/2

Rta: -(3 + √27)/2 < X < -(3 + √27)/2

3x² -8x +11 ≥ 4(x - 1)

3x² -8x +11 ≥ 4x - 4

3x² -12x +15 ≥ 0

x² -4x +5 ≥ 0

x = 2 ± √-1

∄x

Rta: 3x² -8x +11 ≥ 4(x - 1)

∀x