Matemáticas, pregunta formulada por godandy, hace 6 meses

Es para mañana Ayuda plis ​

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Contestado por corderolozaa
1

2 log  - 2 log (x - 1) = 0

log (x) - log (x - 1) = 0                              Propiedad. Log_{a} x - Log_{a} y = Log_{a} \frac{x}{y}

log(\frac{x}{x+1} \\) = 0

\frac{x}{x+1} \\ = 1

x = x + 1

0 = 1          x ∉ 0

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Log (x) = \frac{2 - Log (x)}{log (x)}

Log (x) . Log (x) = 2 - Log (x)                    

Log (x)^{2} = 2 - Log (x)                              Log (x) = A

A^{2} = 2 - A\\A^{2} + A - 2 = 0\\(A + 2)(A - 1) = 0\\A + 2 = 0        ||  A_{1} = -2\\A - 1 = 0        ||  A_{2} = 1\\

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\frac{Log (16-x^{2)} }{Log 3x-4)}=2                                           Propiedad. x . Log_{a}(b)= Log_{a}(b^{x} )

Log (16-x^{2} )=2.Log(3x-4)\\16-x^{2} =(3x-4)^{2} \\16-x^{2} = 9x^{2} -24x+16\\16-x^{2}-9x^{2} +24x-16 = 0\\    -10x^{2} +24 = 0\\-2x(5x-12)=0       (x-2)\\x(5x-12)=0\\x_{1}=0\\x_{2}=12/5

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Log (2) + Log (11-x^{2} )=2 Log (5-x)\\Log(2 . 11-x^{2} )=Log (5-x)^{2} \\Log (22-2x^{2} )=Log (5^{2} -2.(5).(x)+x^{2} )\\Log (22-2x^{2} )=Log (25-10x+x^{2} )\\22-2x^{2} =25-10x+x^{2} \\-3x^{2} +10x-3=0   (. -1)\\3x^{2} -10x+3=0Trinomio de la forma ax²+ bx + c

(3x-1). (x-3)=0\\3x-1=0\\x_{1}=1/3\\-----\\x-3=0\\x_{2} =3\\

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