Question

Es de cálculo diferencial

Answer 1

$y=\frac{2}{x+1}$

$y+4y=\frac{2}{x+1}+4(\frac{2}{x+1})=\frac{2}{x+1}+\frac{8}{x+1}=\frac{2+8}{x+1}=\frac{10}{x+1}$