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Contestado por AmiRexD
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BOYLE'S LAW

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{\underline{\huge \mathbb{P} {\large \mathrm {ROBLEM : }}}} \\

The inflated balloon that slipped from the hand of Renn has a volume of 0.50 L at sea level (1.0 atm) and it reached a height of approximately 8 km where the atmospheric pressure is approximately 0.33 atm. Assuming that the temperature is constant, compute for the final volume of the balloon.

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{\underline{\huge \mathbb{A} {\large \mathrm {NSWER : }}}} \\

 \therefore The final volume of the balloon is 1.5 L.

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{\underline{\huge \mathbb{S} {\large \mathrm {OLUTION : }}}} \\

Given:

The inflated balloon that slipped from the hand of Renn has a volume of 0.50 L.

At sea level (1.0 atm) and it reached a height of approximately 8 km where the atmospheric pressure is approximately 0.33 atm.

Assuming that the temperature is constant, compute for the final volume of the balloon.

In analyzing the problem, it is important that you categorize the initial and final conditions of the variables:

 \begin{gathered}\small\begin{array}{|c|c | }\hline \bold{Initial \: Conditions} & \bold{Final \: Conditions}\\ \hline \tt V_1 = 0.50 \: L & \tt V_2 = \: ? \\ \hline \tt P_1 = 1.0\:atm & \tt P_2 = 0.33\:atm \\  \hline \end{array}\end{gathered} \\

 \bold{Formula:}

 \qquad \quad \boxed{ \bold{ \:  \: V_1 P_1 = V_2 P_2 \:  \: }} \\

So, by using these formula we get:

\\\sf\implies\: V_1 P_1 = V_2 P_2 \\

\sf\implies\: V_2 =  \frac{(V_1)( P_1)} {P_2} \\

\sf\implies\: V_2 =  \frac{(0.50 \: L)( 1.0 \: atm)} {0.33 \: atm} =  \bold{1.5 \: L} \\

 \therefore The final volume of the balloon is 1.5 L.

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