Question

encuentra el valor numérico cuando
$m = 2$
$n = 3$
$p = \frac{1}{2}$
$x = \frac{1}{3}$
$y = 10$
$z = \frac{1}{2}$
​

Answer 1

$\frac{ {m}^{2} + {n}^{2} + y }{p + x}$

(2)^1/2 + (3)^1/2 + 10 /(1/2) + (1/3) =

1,41 + 1,73 + 10 / 3 + 2/6 =

(13,14)/5/6 =

13,14 x 6/5 =

78,84/5 =

15,768