Question

Encuentra el M.C.M y El M.C.D de las siguientes cantidades
A)7,42,56
B)9,10,12

Answer 1

mcm:
7 = 0,7,14,28,,35,42,49,56,63,,70,77,84,,91,97,105,112,119,126,133,140,147,154,161,168,
42 = 0,42,84,126,168,
56 = 0,56,112,168,

mcm de 7,42 y 56 = 168

mcd : 
7 = 1,7
42 = 1,2,3,6,7,14,21,42
56 = 1,2,4,7,8,14,28,56

mcd de 7,42 y 56 = 7

mcm :
9 = 0,9,18,27,36,45,54,63,72,81,90,99,108,117,126,135,144,150,159,168,177,183,,192,201,210,219,228,237,246,255,264,273,282,291,300
10 = 0,10,20,30,40,50,60,70,80,90,100,110,120,130,140,150,160,170,180,190,200,210,220,230,240,250,260,270,280,290,300
12 = 0,12,24,36,48,60,72,,84,96,108,120,132,144,156,168,180,192,204,216,228,240,252,264,276,288,300
mcm de 9,10 y 12 = 300

mcd :
9 = 1,3,9
10 = 1,2,5,10
12 = 1,2,3,4,6,12
mcd de 9,10 y 12 = 1

Answer 2

a)
7 - 42 - 56  sacamos 7
1 - 6 -8      sacamos mitad
1 - 3 - 4     sacamos 4
1 -3 -4     sacamos 3
1 -1 -1
entonces como vemos el M.C.D=7     Y  el M.C.M=7 . 2. 4 .3 =168.

b)9 - 10 - 12    sacamos mitad
 9 - 5 -6           sacamos mitad.
9 - 5 -3            sacamos 3
3 - 5 -1            sacamos 3
1 - 5 -1             sacamos 5
1 -1 -1

enonces el M.C.D=1   y el m.c.m=2.2.3.3.5=180