Question

Encontrar el peso de 250 ml de N medidos a 740 mmHg y 25ºC

Answer 1

V = 50 mL / 1000 = 0.05 L
T = 25 ºC + 273 = 298 K
P = 740 mmHg / 760 = 0.97 atm.
R = 0.0821 (L atm / mol K)

V · P = n · R · T    (Ley de los gases ideales)

despejar n (moles)

n =         0.050 L  ·  0.97 atm
     ``````````````````````````````````````
     0.0821 (Latm/mol K)· 298 K

n = 0.00198 mol

2. calcular masa  mol = masa/Mm
Mm N = 14 g/mol

masa =  mol x Mm
masa = 0.00198 mol x 14 g/mol
masa = 0.02772 g de N