Question

En un triángulo rectángulo ABC recto B.
Reducir =E=b/A senA + b/c senC + c/a tgA

Answer 1

RESOLUCIÓN:

$E = \frac{b}{a} senA + \frac{b}{c} senC + \frac{c}{a} tgA \\ E = \frac{b}{a} \times \frac{a}{b} + \frac{b}{c} \times \frac{c}{b} + \frac{c}{a} \times \frac{a}{c} \\ E = 1 + 1 + 1 \\ E = 3$