Question

En un triángulo isósceles ABC (AB=AC) se sabe que cosa = 0;6
Calcular "tgB"

Answer 1

Si el Cosa=0.6 entonces el Sen(b/2)=0.6

Ahora si el Sen(b/2)=0.6 entonces Cos(b/2)=0.8

Por ello:

$TanB= \frac{SenB}{CosB} = \frac{Sen(2(B/2))}{Cos(2(B/2))}=\frac{2Sen(B/2)Cos(B/2)}{2Cos^{2}(B/2)-1} = \\ \\ \frac{2*0.6*0.8}{2*(0.8^{2})-1} = \frac{0.96}{0.28}= 3.43$