en la siguente ecuacion quimica destruya la ley de la concervacion de la materia ZnS (s) + 02 (g) = Zn0 (s) + S02 (g)
Respuestas a la pregunta
ZnS (s) + 02 (g) → Zn0 (s) + S02 (g)
97,4450 g + 31,9988 g → 81,3794 g + 64,0638 g
123.4438 g = 145.4432 g
No se cumple la Ley de la Conservación de la masa
``````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````````
balanceada la ecuacion química:
2 ZnS(s) + 3 O2(g) → 2 ZnO(s) + 2 SO2(g)
2 ( 97,4450 g) + 3(31,9988 g) = 2 ( 81,3794 g ) + 2(64,0638 g)
194.89 g + 95.9964 g = 162.7588 + 128.1276 g
290.8864 g = 290.8864 g
se cumple la ley de la conservaión de la masa