Question

en cada caso efectuar el producto correspondiente : 1. (-3x)(4x+5) 2. (3y+7)(-4) 3. (3x2)(2x2+3) 4. (2)(2y-1) 6. (-8)(m+2) 7. (5y-7)(-1) 8. (-x2)(2x2-1) 9. (-2)2a 2-5) 10. (2m)(4m2-6m+9) ayudame porfavor.

Answer 1

Respuesta:

Explicación paso a paso:

1. (-3x)(4x+5)=

=(−3x)(4x+5)

=(−3x)(4x)+(−3x)(5)

=−12x2−15x

2. (3y+7)(-4)=

=(3y+7)(−4)

=(3y)(−4)+(7)(−4)

=−12y−28

3. (3x2)(2x2+3)=

=(3x2)(2x2+3)

=(3x2)(2x2)+(3x2)(3)

=6x^4+9x^2

4. (2)(2y-1)=

=(2)(2y+−1)

=(2)(2y)+(2)(−1)

=4y−2

6. (-8)(m+2)=

=(−8)(m+2)

=(−8)(m)+(−8)(2)

=−8m−16

7. (5y-7)(-1) =

=(5y+−7)(−1)

=(5y)(−1)+(−7)(−1)

=−5y+7

8. (-x2)(2x2-1)=

=(−x2)(2x2+−1)

=(−x2)(2x2)+(−x2)(−1)

=−2x^4+x^2

9. (-2)2a 2-5)=

=−8a+−5

=−8a−5

10. (2m)(4m2-6m+9)=

=(2m)(4m2+−6m+9)

=(2m)(4m2)+(2m)(−6m)+(2m)(9)

=8m^3−12m^2+18m

Answer 2

Respuesta:

Explicación paso a paso:

1. (-3x)(4x+5)=

=(−3x)(4x+5)

=(−3x)(4x)+(−3x)(5)

=−12x2−15x

2. (3y+7)(-4)=

=(3y+7)(−4)

=(3y)(−4)+(7)(−4)

=−12y−28

3. (3x2)(2x2+3)=

=(3x2)(2x2+3)

=(3x2)(2x2)+(3x2)(3)

=6x^4+9x^2

4. (2)(2y-1)=

=(2)(2y+−1)

=(2)(2y)+(2)(−1)

=4y−2

6. (-8)(m+2)=

=(−8)(m+2)

=(−8)(m)+(−8)(2)

=−8m−16

7. (5y-7)(-1) =

=(5y+−7)(−1)

=(5y)(−1)+(−7)(−1)

=−5y+7

8. (-x2)(2x2-1)=

=(−x2)(2x2+−1)

=(−x2)(2x2)+(−x2)(−1)

=−2x^4+x^2

9. (-2)2a 2-5)=

=−8a+−5

=−8a−5

10. (2m)(4m2-6m+9)=

=(2m)(4m2+−6m+9)

=(2m)(4m2)+(2m)(−6m)+(2m)(9)

=8m^3−12m^2+18m paso: