Question

El valor de x en la ecuación : log (x + 1) + log ( x – 2) = log (x – 3) + log (x + 5) es x =

Answer 1

Respuesta:

log (x + 1) + log ( x – 2) = log (x – 3) + log (x + 5)

Log[(x+1)(x-2)] = Log[(x-3)(x+5)]

10^( Log[(x+1)(x-2)] ) = 10 ^ [ Log[(x-3)(x+5)]

10^( Log[ x^2+x-2 ] ) = 10^( Log[ x^2-2x-15 ] )

x^2 +x-2 = x^2-2x-15.

(1-1)x^2+x-2 = -2x-15

x-2 = -2x-15.

(1+2)x-2 = -15

3x-2 = -15

3x-2+2 = -15+2

3x = -13

3x/3 = -13/3

x = -13/3

Explicación paso a paso: