Question

El ejercicio 1 y 2 please es para hoy

Answer 1

1)

$2x - (3(x - 1) + {( - 1)}^{4} ) = x(3 - 2) + {( - 4)}^{2} \\ 2x - (3x - 3 + 1) = 3x - 2x + 16 \\ 2x - (3x - 2) = x + 16 \\ 2x - 3x + 2= x + 16 \\ - x + 2= x + 16 \\ 2 - 16 = x + x \\ - 14 = 2x \\ \frac{ - 14}{2} = \times \\ \\ - 7 = x$