Question

El cloro y el metano reaccionan para formar el cloroformo según la siguiente reacción CH4 + 3Cl2=CHCl3 + 3HClEstablezca el reactivo límite A) 1.5 molesCl2 y 1.5 miles de CH4 B) 2 moles de Cl2 y 3 moles de CH4 C) 0.5 moles de Cl2 y 0.20 moles de CH4 D) 0.2 moles de Cl2 y 0.3 moles de CH4 E) 2 moles de Cl2 y 7 moles de CH4

Answer 1

                         CH4 + 3Cl2 → CHCl3 + 3HCl

a.calcular moles a partir de la reacción:

mol CHCl3 = 1.5 mol Cl2 x 1 mol  CHCl3
                                            ``````````````````
                                              3 mol Cl2

moll CHCl3 = 0.5

mol CHCl3 = 1.5 mol CH4  x  1 mol CHCl3
                                               ``````````````````
                                                  1 mol CH4

mol CHCl3 = 1.5

REACTIVO LIMITANTE: Cloro (produce 0.5 mol de CHCl3)

b.

mol CHCl3 = 2 mol Cl2  x  1 mol CHCl3
                                          ```````````````````
                                             3 mol Cl2
mol CHCl3 = 0.67

mol CHCl3 = 3 mol CH4 x 1 mol CHCl3
                                           ``````````````````
                                            1 mol CH4
mol CHCl3 = 3 mol

REACTIVO LIMITANTE: Cloro (produce 0.67 mol de CHCl3)

c.
calcular moles a partir de la reacción:

mol CHCl3 = 0.5 mol Cl2 x 1 mol  CHCl3
                                            ``````````````````
                                              3 mol Cl2

moll CHCl3 = 0.167

mol CHCl3 = 0.20 mol CH4  x  1 mol CHCl3
                                                 ``````````````````
                                                   1 mol CH4

mol CHCl3 = 0.20

REACTIVO LIMITANTE: Cloro (produce 0.167 mol de CHCl3)

d.
calcular moles a partir de la reacción:

mol CHCl3 = 0.2 mol Cl2 x 1 mol  CHCl3
                                            ``````````````````
                                              3 mol Cl2

moll CHCl3 = 0.067

mol CHCl3 = 0.3 mol CH4  x  1 mol CHCl3
                                               ``````````````````
                                                  1 mol CH4

mol CHCl3 = 0.3

REACTIVO LIMITANTE: Cloro (produce 0.067 mol de CHCl3)

e.
calcular moles a partir de la reacción:

mol CHCl3 = 2 mol Cl2  x    1 mol  CHCl3
                                            ``````````````````
                                              3 mol Cl2

moll CHCl3 = 0.67

mol CHCl3 =    7 mol CH4  x  1 mol CHCl3
                                               ``````````````````
                                                  1 mol CH4

mol CHCl3 = 7

REACTIVO LIMITANTE: Cloro (produce 0.67 mol de CHCl3)