Question

el analisis de un cierto insecticida, nos da la siguiente composicion porcentual: carbono (C) 24.7%, hidrogeno (H) 2.06% y cloro(CL) 73.2%, con una masa molecular de 291 uma . calcula la formula molecular del compuesto

Answer 1

C: 24.7 g/ 12 g/mol = 2.058 mol
H: 2.06 g / 1 g/mol = 2.06 mol
Cl: 73.2 g / 35.5 g/mol = 2.062 mol
dividir

C: 2.058 mol / 2.058 mol = 1
H: 2.06 mol / 2.058 mol = 1
Cl: 2.062 mol / 2.058 mol = 1

FE: CHCl
M FE

C. 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
Cl: 1 x 35.5 = 35.5 g/mol
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 Mm = 49 g/mol

n = 291 / 49 = 6

FM: (CHCl)6 = C6H6Cl6