Question

EJERCICIO: Resuelve las siguientes sustracciones de polinomios

( 4m2 + 6m – 1 ) – ( 2m2 + 4m + 8 ) =

( 7y3 – 2y2 + 6y – 1 ) – ( 2y2 + 4y + 2 ) =

(3x4 – 2x3 – 2x + 6x2

) – ( 2x4 + 4x3 – 2x2
) =

( 4a4 – 2a2 + 6a + 1 ) – ( 2a2 + 7a + 2 ) =

( 5m2n + 6mn2 + 4m2n
2
) – ( 6m2n – 7m2n ) =

Answer 1

Respuesta:

A)$\left(4m\cdot \:2+6m-1\right)-\left(2m\cdot \:2+4m+8\right)$

   $=4m\cdot \:2+6m-1-\left(2m\cdot \:2+4m+8\right)$

   $=8m+6m-1-\left(8m+8\right)$

   $=8m+6m-1-8m-8$

   $=6m-9$

B)$\left(7y\cdot \:3-2y\cdot \:2+6y-1\right)-\left(2y\cdot \:2+4y+2\right)$

   $=7y\cdot \:3-2y\cdot \:2+6y-1-\left(2y\cdot \:2+4y+2\right)$

   $=21y-4y+6y-1-\left(8y+2\right)$

   $=21y-4y+6y-1-8y-2$

   $=15y-3$

C)$\left(3x\cdot \:4-2x\cdot \:3-2x+6x\cdot \:2\right)-\left(2x\cdot \:4+4x\cdot \:3-2x\cdot \:2\right)$

   $=3x\cdot \:4-2x\cdot \:3-2x+6x\cdot \:2-\left(2x\cdot \:4+4x\cdot \:3-2x\cdot \:2\right)$

   $=12x-6x-2x+12x-16x$

   $=0$

D)$\left(4a\cdot \:4-2a\cdot \:2+6a+1\right)-\left(2a\cdot \:2+7a+2\right)$

   $=4a\cdot \:4-2a\cdot \:2+6a+1-\left(2a\cdot \:2+7a+2\right)$

   $=16a-4a+6a+1-\left(11a+2\right)$

   $=16a-4a+6a+1-11a-2$

   $=7a-1$

E)$\left(5m\cdot \:2n+6mn\cdot \:2+4m\cdot \:2n\cdot \:2\right)-\left(6m\cdot \:2n-7m\cdot \:2n\right)$

   $=5m\cdot \:2n+6mn\cdot \:2+4m\cdot \:2n\cdot \:2-\left(6m\cdot \:2n-7m\cdot \:2n\right)$

   $=10mn+12mn+16mn+2mn$

   $=40mn$