Question

Efectuar (x+5)elevado a la 2-(x-5)elevado a la 2 -20x
Efectuar (1+x)(x-1)-(4+x)(x-4)

Answer 1

Respuesta:

Explicación paso a paso:

\left(x+5\right)^2-\left(x-5\right)^2-20x=0

=x^2+10x+25-\left(x-5\right)^2-20x

=x^2+10x+25-x^2+10x-25-20x

=x^2-x^2+10x+10x-20x+25-25

=10x+10x-20x+25-25

=25-25

=0

\left(1+x\right)\left(x-1\right)-\left(4+x\right)\left(x-4\right)=15

=x^2-1-\left(4+x\right)\left(x-4\right)

=x^2-1-x^2+16
=x^2-x^2-1+16

=1-16

=15