Question

efectúa las operaciones entre potencias aplicando las propiedades
a. [(1/3)²]⁴:
b. [(2-³)⁶]:
c. [(2/3)²]-¹:
d. [2³*2-⁹*4²)⁴]÷(1/4)-²​

Answer 1

Respuesta:

Explicación paso a paso:

a. [(1/3)²]⁴ = $(\frac{1}{3} )^{8}= \frac{1}{3^{8} } =\frac{1}{6561}$  

b. [(2-³)⁶] = $2^{-18} = \frac{1}{2^{18} } = \frac{1}{262144}$

c. [(2/3)²]-¹ = $(\frac{2}{3} )^{-2} = (\frac{3}{2} )^{2} = \frac{3^{2} }{2^{2} } = \frac{9}{4}$

d. [2³*2-⁹*4²)⁴]÷(1/4)-²​

   [$2^{3-9+2} *(2^{2} )^{2}$]÷$(\frac{1}{4} )^{-2}$

    ($2^{-4} *2^{4}$) ÷ 4²

    $2^{-4+4}$ ÷ 4²

     $2^{0}$ ÷ 16

     1 ÷ 16

     $\frac{1}{16}$