Question

efectua la siguiente operacion:
$2\sqrt[3]{40} + 7\sqrt[3]{16} + 5 \sqrt[3]{250}- \sqrt[3]{5000}$

Answer 1

Respuesta:

Simplifica \sqrt[3]{40}

3

40

a 2\sqrt[3]{5}2

3

5

.

2\times 2\sqrt[3]{5}\times 7+\sqrt[3]{16}+5\sqrt[3]{250}-\sqrt[3]{5000}

2×2

3

5

×7+

3

16

+5

3

250

−

3

5000

2 Simplifica \sqrt[3]{16}

3

16

a 2\sqrt[3]{2}2

3

2

.

2\times 2\sqrt[3]{5}\times 7+2\sqrt[3]{2}+5\sqrt[3]{250}-\sqrt[3]{5000}

2×2

3

5

×7+2

3

2

+5

3

250

−

3

5000

3 Simplifica \sqrt[3]{250}

3

250

a 5\sqrt[3]{2}5

3

2

.

2\times 2\sqrt[3]{5}\times 7+2\sqrt[3]{2}+5\times 5\sqrt[3]{2}-\sqrt[3]{5000}

2×2

3

5

×7+2

3

2

+5×5

3

2

−

3

5000

4 Simplifica \sqrt[3]{5000}

3

5000

a 10\sqrt[3]{5}10

3

5

.

2\times 2\sqrt[3]{5}\times 7+2\sqrt[3]{2}+5\times 5\sqrt[3]{2}-10\sqrt[3]{5}

2×2

3

5

×7+2

3

2

+5×5

3

2

−10

3

5

5 Simplifica 2\times 2\sqrt[3]{5}\times 72×2

3

5

×7 a 28\sqrt[3]{5}28

3

5

.

28\sqrt[3]{5}+2\sqrt[3]{2}+5\times 5\sqrt[3]{2}-10\sqrt[3]{5}

28

3

5

+2

3

2

+5×5

3

2

−10

3

5

6 Usa Regla del Producto: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

28\sqrt[3]{5}+{2}^{\frac{4}{3}}+5\times 5\sqrt[3]{2}-10\sqrt[3]{5}

28

3

5

+2

3

4

+5×5

3

2

−10

3

5

7 Simplifica 5\times 5\sqrt[3]{2}5×5

3

2

a 25\sqrt[3]{2}25

3

2

.

28\sqrt[3]{5}+{2}^{\frac{4}{3}}+25\sqrt[3]{2}-10\sqrt[3]{5}

28

3

5

+2

3

4

+25

3

2

−10

3

5

Hecho

Forma Decimal: 64.797435