Efectúa:
a) (9,536 · 103) + (5,63 · 103)
b) (2,754 · 10−4)3
c) (5,21 · 103) : (2,07 · 10−4)
d) (3,47 · 105) · (1,1 · 10−5)
e) (1,1427 · 1011)−1
f) (2,3 · 107) · (4,5 · 10−3) : (9,1 · 105)
g) (3,7 · 10−4) − (7,83 · 10−4)
Respuestas a la pregunta
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a)
(9.536•103) + (5.63•103) =
982.208 + 579.89 =
1562.098
b)
(2.754•10-4)3 =
(2.754•6)3 =
(16.524)3 =
49.572
c)
(5.21•103) : (2.07•10-4) =
(536.63) : (2.07•6) =
536.63 : 12.42 =
43.206
d)
(3.47•105)•(1.1•10-5) =
(364.35) • (1.1•5) =
364.35 • 5.5 =
2003.925
e)
(1.1427•1011)-1 =
1155.269 - 1 =
1154.269
f)
(2.3•107)•(4.5•10-3):(9.1•105) =
(246.1) • (4.5•7) : (955.5) =
246.1 • 31.5 : 955.5 =
7752.15 : 955.5 =
8.113
g)
(3.7•10-4) - (7.83•10-4) =
(3.7•6) - (7.83•6) =
(22.2) - (46.98) =
22.2 - 46.98 =
- 24.78
(9.536•103) + (5.63•103) =
982.208 + 579.89 =
1562.098
b)
(2.754•10-4)3 =
(2.754•6)3 =
(16.524)3 =
49.572
c)
(5.21•103) : (2.07•10-4) =
(536.63) : (2.07•6) =
536.63 : 12.42 =
43.206
d)
(3.47•105)•(1.1•10-5) =
(364.35) • (1.1•5) =
364.35 • 5.5 =
2003.925
e)
(1.1427•1011)-1 =
1155.269 - 1 =
1154.269
f)
(2.3•107)•(4.5•10-3):(9.1•105) =
(246.1) • (4.5•7) : (955.5) =
246.1 • 31.5 : 955.5 =
7752.15 : 955.5 =
8.113
g)
(3.7•10-4) - (7.83•10-4) =
(3.7•6) - (7.83•6) =
(22.2) - (46.98) =
22.2 - 46.98 =
- 24.78
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