Question

ecuaciones quien me ayuda a resolver porfavor​

Answer 1

Respuesta:

buscar en google

Explicación paso a paso:

paso a paso

Answer 2

Respuesta:

Yo te ayudo

A) 4

B) 3

C) 6

D) 44

E) 3, - 5

F) 14

G) 1

H) 5

Explicación paso a paso:

A)

$3x + 7 = x + 15 \\ 3x - x = 15 - 7 \\ 2x = 8 \\ x = \frac{8}{2} \\ x = 4$

B)

${x}^{2} + 5 = 14 \\ {x}^{2} = 14 - 5 \\ {x}^{2} = 9 \\ x = \sqrt{9} \\ x = 3$

C)

$9x + 7 = 6x + 25 \\ 9x - 6x = 25 - 7 \\ 3x = 18 \\ x = \frac{18}{3} \\ x = 6$

D)

$\sqrt{x + 5} = 7 \\ {( \sqrt{x + 5} )}^{2} = {7}^{2} \\ x + 5 = 49 \\ x = 49 - 5 \\ x = 44$

E)

$3 {(x + 1})^{2} = 48 \\ 3( {x}^{2} + 2(x)(1) + {1}^{2} = 48 \\ 3( {x}^{2} + 2x + 1) = 48 \\ 3 {x}^{2} + 6x + 3 = 48 \\ 3 {x}^{2} + 6x + 3 - 48 = 0 \\ 3 {x}^{2} + 6x - 45 = 0 \\ 3x \: \: \: \: \: \: \: \: \: \: \: \: \: \: - 9 \\ x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 5 \\ \\ 3x - 9 = 0 \\ 3x = 9 \\ x = \frac{9}{3} \\ x = 3 \\ \\ x + 5 = 0 \\ x = - 5$

F)

$\sqrt[3]{2x - 1} + 2 = 5 \\ \sqrt[3]{2x - 1} = 5 - 2 \\ \sqrt[3]{2x - 1} = 3 \\ {( \sqrt[3]{2x - 1} )}^{3} = {3}^{3} \\ 2x - 1 = 27 \\ 2x = 27 + 1 \\ 2x = 28 \\ x = \frac{28}{2} \\ x = 14$

G)

$\sqrt{7x + 9} + 5 = 9 \\ \sqrt{7x + 9} = 9 - 5 \\ \sqrt{7x + 9} = 4 \\ {( \sqrt{7x + 9}) }^{2} = {4}^{2} \\ 7x + 9 = 16 \\ 7x = 16 - 9 \\ 7x = 7 \\ x = \frac{7}{7} \\ x = 1$

H)

$7 + 2 {x}^{2} = 57 \\ 2 {x}^{2} = 57 - 7 \\ 2 {x}^{2} = 50 \\ {x }^{2} = \frac{50}{2} \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5$