Question

ecuaciones matemáticas                    4x+3(y-1)=5    3(y-1)=2x-7      

Answer 1

$4x+3(y-1)=5 \\ 3(y-1)=2x-7 \\ \\ 4x+(3x-3)=5 \\ (3y-3)= 2x - 7 \\ \\ 4x + 2x - 7 = 5 \\ 4x + 2x = 5 + 7 \\ 6x = 12 \\ x= \frac{12}{6} \\ x=2 \\ \\ 3y - 3 = 2 \times 2 - 7 \\ 3y=4-7+3 \\ 3y=0 \\ y= \frac{0}{3} \\ y=0$

Answer 2

Resolver
4x +3( y -1) = 5 (1)
3(y -1) = 2x -7 (2)

metodo de eliminacion

4x + 3(y -1) = 5
4x + 3y - 3 = 5
4x +3y - 3 - 5= 0
4x +3y - 8 = 0 (1)


3( y -1) = 2x -7
3y - 3 = 2x -7
3y -3-2x +7 =0
-2x +3y +4 = 0 (2)

 4x + 3y -8 = 0 (1)
-2x +3y +4 = 0 (multiplicamos por (-1) = 2x - 3y -4 = 0 (2)

sumamos (1) y (2)
 4x +3y -8 = 0
2x -3y -4 = 0
-------------------
6x -12 = 0
6x = 12
x = 12/6
x = 2

remplazamos el valor de x en (2)
3( y -1) = 2x -7
3( y-1) = 2*2 -7
3( y-1) = 4 -7
y -1 = -3/3
y -1 = -1
y = -1+1
y = 0
Soluciones
x = 2 , Y = 0