ecuaciones de segundo grado con una incognita
Adjuntos:
ageot:
ayudenme xfaaaa
Respuestas a la pregunta
Contestado por
13
a)
x² - 4 = 0
x² = 4
x = √4
x = 2 ==>>> Respuesta
-------------------------------------------------------------------------------------------------
b)
x² - 36 = 0
x² = 36
x = √36
x = 6 ==>>> Respuesta
-------------------------------------------------------------------------------------------------------
c)
x² - 3x = 0
x² - 3x + 0 = 0
x -3 => (x - 3)
x 0 => (x + 0)
Entonces:
x - 3 = 0
x = 3 => Solucion 1
x + 0 = 0
x = 0 => Solucion 2
RESPUESTA:
==========
X = [ 0 ; 3]
------------------------------------------------------------------------------------------------------
d)
x² + 5x = 0
x² + 5x + 0 = 0
x 5 => (x + 5)
x 0 => (x + 0)
Entonces:
x + 5 = 0
x = -5 => Solucion 1
x + 0 = 0
x = 0 => Solucion 2
RESPUESTA:
===========
x = [ -3 ; 0 ]
------------------------------------------------------------------------------------------------
e)
x² - 25 = 0
x² + 0 - 25 = 0
x -5 => )x - 5)
x 5 => )x + 5)
Entonces:
x - 5 = 0
x = 5 => Solucion 1
x + 5 = 0
x = -5 => Solucion 2
RESPUESTA:
============
x = [ -5 ; 5 ]
-------------------------------------------------------------------------------------------------------
f)
4x - 64 = 0
4x² + 0 - 64 = 0
2x -8 => (2x - 8)
2x 8 => (2x + 8)
Entonces:
2x - 8 = 0
2x = 8
x = 8÷ 2
x = 4 => => solucion 1
2x + 8 = 0
2x = -8
x = -8 ÷ 2
x = -4 => => solucion 2
RESPUESTA:
============
X = [ -4 ; 4 ]
----------------------------------------------------
Espero que te sirva
Saludos!!!
x² - 4 = 0
x² = 4
x = √4
x = 2 ==>>> Respuesta
-------------------------------------------------------------------------------------------------
b)
x² - 36 = 0
x² = 36
x = √36
x = 6 ==>>> Respuesta
-------------------------------------------------------------------------------------------------------
c)
x² - 3x = 0
x² - 3x + 0 = 0
x -3 => (x - 3)
x 0 => (x + 0)
Entonces:
x - 3 = 0
x = 3 => Solucion 1
x + 0 = 0
x = 0 => Solucion 2
RESPUESTA:
==========
X = [ 0 ; 3]
------------------------------------------------------------------------------------------------------
d)
x² + 5x = 0
x² + 5x + 0 = 0
x 5 => (x + 5)
x 0 => (x + 0)
Entonces:
x + 5 = 0
x = -5 => Solucion 1
x + 0 = 0
x = 0 => Solucion 2
RESPUESTA:
===========
x = [ -3 ; 0 ]
------------------------------------------------------------------------------------------------
e)
x² - 25 = 0
x² + 0 - 25 = 0
x -5 => )x - 5)
x 5 => )x + 5)
Entonces:
x - 5 = 0
x = 5 => Solucion 1
x + 5 = 0
x = -5 => Solucion 2
RESPUESTA:
============
x = [ -5 ; 5 ]
-------------------------------------------------------------------------------------------------------
f)
4x - 64 = 0
4x² + 0 - 64 = 0
2x -8 => (2x - 8)
2x 8 => (2x + 8)
Entonces:
2x - 8 = 0
2x = 8
x = 8÷ 2
x = 4 => => solucion 1
2x + 8 = 0
2x = -8
x = -8 ÷ 2
x = -4 => => solucion 2
RESPUESTA:
============
X = [ -4 ; 4 ]
----------------------------------------------------
Espero que te sirva
Saludos!!!
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