Question

Ecuaciones de primer grado con una incógnita
es para hoy :C
doy corona

Answer 1

$\textbf{Resolvemos:}\\\\\dfrac{x+4}{3}-\dfrac{x+12}{6}=\dfrac{x-2}{12}\\\\\\12\cdot\dfrac{x+4}{3}-12\cdot\dfrac{x+12}{6}\right)=12\cdot\dfrac{x-2}{12}\\\\\\4\ (x+4)-2\ (x+12)=x-2\\\\\\4x+16-2x-24=x-2\\\\\\2x-8=x-2\\\\\\2x-x=8-2\\\\\\\boxed{\mathbf{x=6}}$