Question

E= (x+1)(x+2)+(x+3)(x+4)-2x(x+5)

Answer 1

$\frac{d}{dx} ((x+1)(x+2)+(x+3)(x+4)-2x(x+5))$

$=\frac{d}{dx} ((x+1)(x+2)+\frac{d}{dx} ((x+3)(x+4))-\frac{d}{dx} (2x(x+5))$

$\frac{d}{dx} ((x+1)(x+2))=2x+3$

$\frac{d}{dx} ((x+3)(x+4))=2x+7$

$\frac{d}{dx} (2x(x+5))=2(2x+5)$

$=2x+3+2x+7-2(2x+5)$

$Simplificar: =2x+3+2x+7-2(2x+5) = 0$

$De~nada!! (Y~si~te~ayudo~por~favor~da~click~en~Gracias,$

$dame~5~estrellas~y~elige~mi~respuesta~como~la~mejor! :)$

Answer 2

Respuesta:

14

Explicación paso a paso:

E= (x+1)(x+2)+(x+3)(x+4)-2x(x+5)

E=x.x+(1+2)x+1.2 + x.x+(3+4)x+3.4 -2x.x -2x.5

E=x2+3x+2+x2+7x+12-2x2-10x

E=12+2

E=14