Matemáticas, pregunta formulada por dignafranco243, hace 4 meses

e (2x +y + 22 =2 13x-y-22= -6 1-3x+y + 10 Z=6​

Respuestas a la pregunta

Contestado por darwinstevenva
0

Respuesta:

x = -1/7 , y = -138/7 , z = 85/7

2x +y + 22 = 2. (1)

13x-y-22= -6. (2)

1-3x+y+10z = 6​ (3)

Método de Sustitución :

1 ) Despejamos " x " en " 13x-y-22 = -6 " :

13x-y-22 = -6

13x-y-22+22 = -6+22

13x-y = 16

13x-y+y = 16+y

13x = 16+y

13x/13 = (16+y)/13

x = (16+y)/13

2 ) Reemplazamos a " x = (16+y)/13 " en " 2x+y+22 = 2 " :

2((16+y)/13)+y+22 = 2

13((16+y)/13)+13(y)+13(22) = 13(2)

16+y+13y+286 = 26

16+14y+286 = 26

14y+302 = 26

14y/2+302/2 = 26/2

7y+151 = 13

7y+151-151 = 13-151

7y = -138

7y/7 = -138/7

y = -138/7

3 ) Sustituimos " y = -138/7 '' en '' 2x+y+22 = 2 '' :

2x+(-138/7)+22 = 2

2x-138/7+22 = 2

7(2x)-7(138/7)+7(22) = 2(7)

14x - 138+154 = 14

14x +16 = 14

14x/2+16/2 = 14/2

7x + 8 = 7

7x+8-8 = 7-8

7x = -1

7x/7 = -1/7

x = -1/7

4 ) Sustituimos a " x = -1/7 " y a " y = -138/7 " en " 1-3x+y+2z = 6 " :

1-3(-1/7)+(-138/7)+2z = 6

1+3/7-138/7 + 2z = 6

1+(-135/7)+2z = 6

1-135/7 + 2z = 6 , 1 = 7/7

7/7-135/7 +2z = 6

-128/7 + 2z = 6

7(-128/7)+7(2z) = 6(7)

-128+14z = 42

-128+14z+128 = 42+128

14z = 170

14z/2 = 170/2

7z = 85

7z/7 = 85/7

z = 85/7

Explicación paso a paso:

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