Question

DX=(x²-2x+1)(2x²+3x)​

Answer 1

Respuesta:

$x\left(x\right)=c_1+\int \left(x\left(x\right)^2-2x\left(x\right)+1\right)\left(2x\left(x\right)^2+3x\left(x\right)\right)dx$

Explicación paso a paso:

DX=(x²-2x+1)(2x²+3x)​:

$Dx\left(x\right)=\left(x\left(x\right)^2-2x\left(x\right)+1\right)\left(2x\left(x\right)^2+3x\left(x\right)\right)$

$x\left(x\right)=c_1+\int \left(x\left(x\right)^2-2x\left(x\right)+1\right)\left(2x\left(x\right)^2+3x\left(x\right)\right)dx$

Raíces de:

$x\left(x\right)=c_1+\int \left(x\left(x\right)^2-2x\left(x\right)+1\right)\left(2x\left(x\right)^2+3x\left(x\right)\right)dx$

Espero haberte ayudado dame coronita xfa ;)