Question

doy estrellas y coronas

resuelve las siguiente ecuaciones por descomposición factorial

(x-1)(x+2)=x+(2x-3)(x+4)+14​

Answer 1

Respuesta:

(x-1)(x+2) = x+(2x-3)(x+4)+14​

x^2+x - 2 = x + 2x^2+5x-12+14

x^2+x-2 = 2x^2+6x-12

x-2 = (2-1)x^2+6x-12

x-2 = x^2+6x-12

x-2+12 = x^2+6x-12+12

x + 10 = x^2+6x

x+10-x = x^2+6x-x

10 = x^2+5x

10-10 = x^2+5x-10

0 = x^2+5x-10

x^2+5x-10 = 0

x = ( -(5)+-√((5)^2-4(1)(-10))/(2(1))

x = ( -5+-√(25-(-40)))/2

x = ( -5+-√(25+40))/2

x = ( -5+-√(65))/2

X1 = (-5-√(65))/2

X2 = ( -5+√(65))/2

Explicación paso a paso: