Matemáticas, pregunta formulada por carlos725538, hace 3 meses

doy coronita quien me ayude
procedimiento quiero​

Adjuntos:

carlos725538: gracias

Respuestas a la pregunta

Contestado por Usuario anónimo
2

RESOLVER:

PRIMER PUNTO:

a) \left(5^3\cdot \:2^2\cdot \:4^3\right)^2

=\left(5^3\right)^2\cdot \left(2^2\right)^2\cdot \left(4^3\right)^2

=15625\cdot \:16\cdot \left(4^3\right)^2

=15625\cdot \:16\cdot \:4^{3\cdot \:2}

=15625\cdot \:16\cdot \:4^6

=15625\cdot \:16\cdot \:4096

\boxed{=1024000000}

b) 3^2\cdot \:3^3\left(\frac{3^3\cdot \:3^4}{3^4\cdot \:3^2}\right)

=3^2\cdot \:3^3\cdot \frac{3^3\cdot \:3^4}{3^4\cdot \:3^2}

=243\cdot \frac{3^3\cdot \:3^4}{3^4\cdot \:3^2}

=\frac{3^3\cdot \:3^4\cdot \:243}{3^4\cdot \:3^2}

=\frac{3^3\cdot \:243}{3^2}

=243\cdot \:3^{3-2}

=3\cdot \:243

\boxed{=729}

c) \left(\frac{3\cdot \:2^3}{2^2\cdot \:3^2}\right)^2

=\frac{\left(3\cdot \:2^3\right)^2}{\left(2^2\cdot \:3^2\right)^2}

=\frac{576}{\left(2^2\cdot \:3^2\right)^2}

=\frac{576}{1296}

\boxed{=\frac{4}{9}}

SEGUNDO PUNTO:

a) \left(5^2\right)^3

=5^{2\cdot \:3}

\boxed{5^6=15625}

b) \left[\left(\frac{3}{7}\right)^2\right]^5

=\left(\frac{3}{7}\right)^{2\cdot \:5}

\boxed{=\left(\frac{3}{7}\right)^{10}=\frac{59049}{282475249}}

c) \left(\frac{4}{5}\right)^4

=\frac{4^4}{5^4}

\boxed{=\frac{256}{625}}

TERCER PUNTO:

a) \sqrt[3]{\frac{81}{3}}\cdot \:3^4\cdot \frac{1}{3^4}

=\frac{1\cdot \sqrt[3]{\frac{81}{3}}\cdot \:3^4}{3^4}

=1\cdot \sqrt[3]{\frac{81}{3}}

=1\cdot \:3

\boxed{3}

b) \frac{\left(\sqrt{49}\sqrt{49}\sqrt{49}\sqrt{49}\right)^2}{\left(\left(\sqrt{49}\right)^2\right)^3}

=\frac{\left(49^{4\cdot \frac{1}{2}}\right)^2}{\left(\left(\sqrt{49}\right)^2\right)^3}

=\frac{\left(49^{4\cdot \frac{1}{2}}\right)^2}{49^3}

=\frac{49^4}{49^3}

=49^{4-3}

\boxed{49}

c) \frac{10^2\cdot \:10^3\sqrt[3]{1000}\cdot \:10^4}{\left(\sqrt[4]{10000}\sqrt[3]{1000}\right)^2}

=\frac{10^2\cdot \:10^3\cdot \:10\cdot \:10^4}{\left(\sqrt[4]{10000}\sqrt[3]{1000}\right)^2}

=\frac{10^{10}}{\left(\sqrt[4]{10000}\sqrt[3]{1000}\right)^2}

\boxed{=1000000}

d) \frac{\left(8+2\right)^2\left(12-2\right)^2\cdot \:10^3\left(3^2+1\right)}{\left(20+2\right)\sqrt{100}\sqrt[3]{1000}\sqrt[4]{10000}}

=\frac{\left(8+2\right)^2\left(12-2\right)^2\cdot \:10^3\left(3^2+1\right)}{\left(20+2\right)\cdot \:10\sqrt[3]{1000}\sqrt[4]{10000}}

=\frac{\left(8+2\right)^2\left(12-2\right)^2\cdot \:10^3\left(3^2+1\right)}{\left(20+2\right)\cdot \:10\cdot \:10\sqrt[4]{10000}}

=\frac{\left(8+2\right)^2\left(12-2\right)^2\cdot \:10^3\left(3^2+1\right)}{\left(20+2\right)\cdot \:10\cdot \:10\cdot \:10}

=\frac{10^2\cdot \:10^2\cdot \:10^3\left(3^2+1\right)}{22\cdot \:10^3}

=\frac{5000\left(3^2+1\right)}{11}

\boxed{=\frac{50000}{11}}

Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)


carlos725538: muchas gracias
carlos725538: me podrías ayudar en otro porfas
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