Question

DOY CORONITA

1) 3x –12 = x + 2

2) 4x –17 = -6x - 82

3) 6y +3 = 3y + 9

4) -3x+2 = 9x -3

5) 5n -5= 2n +1

Answer 1

ΗΘΙΑ

procedimiento :

1)

3x−12=x+2

$3x-12-x=x+2-x$

$2x-12=2$

$2x-12+12=2+12$

$2x=14$

$2x/2=14/2$

$\boxed{x=1}$

2)

4x –17 = -6x - 82

$4x-17+6x=-6x-82+6x$

$10x-17=-82$

$10x-17+17=-82+17$

$10x=-65$

$\frac{10x}{10} \frac{-65}{10}$

$\boxed{x=\frac{-13}{2} }$

3)

6y +3 = 3y + 9

$6y+3-3y=3y+9-3y$

$3y+3=9$

$3y+3-3=9-3$

$3y=6$

$\frac{3y}{3}= \frac{6}{3}$

$\boxed{y=2}$

4)

-3x+2 = 9x -3

$-3x+2-9x=9x-3-9x$

$-12x+2=-3$

$-12x+2-2=-3-2$

$-12x=-5$

$\frac{-12x}{-12} \frac{-5}{-12}$

$\boxed{x=\frac{5}{2} }$

5)

5n -5= 2n +1

$5n-5-2n=2n+1-2n$

$3n-5=1$

$3n-5+5=1+5$

$3n=6$

$\frac{3n}{3}= \frac{6}{3}$

$\boxed{n=2}$

salu2!!