Question

(doy corona)resultado + ecuación y también si se puede la fracción irredusible​

Answer 1

Explicación paso a paso:

$\frac{4}{3} + 1 - \frac{2}{3} \\ \frac{4}{3} + \frac{3}{3} - \frac{2}{3} \\ \frac{7}{3} - \frac{2}{3} = \frac{5}{3}$

$2 \times \frac{4}{3} - \frac{4}{6} + 1 \\ 2 \times \frac{8}{6} - \frac{4}{6} + 1 \\ \frac{16}{6} - \frac{4}{6} + \frac{6}{6} \\ \frac{12}{6} + \frac{6}{6} \\ \frac{18}{6} = 3$

$\frac{5}{6} + \frac{4}{3} - \frac{1}{6} \\ \frac{5}{6} + \frac{4}{6} - \frac{1}{6} \\ \frac{9}{6} - \frac{1}{6} \\ \frac{8}{6} = \frac{4}{3}$

$- \frac{5}{3} + \frac{15}{9} \div \frac{1}{3} \\ - \frac{5}{3} + \frac{45}{9} \\ - \frac{15}{9} + \frac{45}{9} \\ \frac{30}{9} = \frac{10}{3}$

$( \frac{4}{7} \div \frac{2}{7} ) \times \frac{1}{3} + \frac{5}{3} \\ \frac{28}{14} \times \frac{1}{3} + \frac{5}{3} \\ 2 \times \frac{1}{3} + \frac{5}{3} \\ \frac{2}{3} + \frac{5}{3} = \frac{7}{3}$

$5 \div \frac{3}{4} - \frac{10}{6} \\ \frac{20}{3} - \frac{5}{3} \\ \frac{15}{3} = 5$

$\frac{6}{7} \div \frac{3}{5} - \frac{3}{7} \\ \frac{30}{28} - \frac{3}{7} \\ \frac{15}{14} - \frac{6}{14} = \frac{9}{14}$

$(4 + ( - \frac{1}{3} )) \div \frac{11}{2} \\ (4 - \frac{1}{3} ) \div \frac{11}{2} \\ (\frac{12}{3} - \frac{1}{3} ) \div \frac{11}{2} \\ \frac{11}{3} \div \frac{11}{2} \\ \frac{22}{33} = \frac{2}{3}$

$- \frac{4}{3} \times \frac{5}{2} + 3 \\ - \frac{20}{6} + 3 \\ - \frac{10}{3} + 3 \\ - \frac{10}{3} + \frac{9}{3} = - \frac{1}{3}$

$\frac{2}{3} + \frac{14}{21} \\ \frac{2}{3} + \frac{2}{3} = \frac{4}{3}$