Question

doy corona por fracciones resolverlo y te las doy ​

Answer 1

Respuesta:

3.-

a)

$\frac{1}{3} + \frac{1}{2} +\frac{1}{9}$

$\frac{2}{6} +\frac{2}{4} +\frac{2}{18} =\frac{24+36+8}{72} =\frac{68}{72} =\frac{17}{18}$

b)

$\frac{3}{4} +\frac{2}{3} -\frac{5}{6}$

$\frac{6}{8} +\frac{4}{6} -\frac{10}{12}=\frac{36+32-40}{48} =\frac{28}{48} =\frac{7}{12}$

c)

$\frac{3}{2} -\frac{4}{5} +\frac{1}{3}$

$\frac{6}{4} -\frac{8}{10} +\frac{2}{6}=\frac{90-48+20}{60} =\frac{68}{60}=\frac{17}{15}$

d)

$\frac{7}{6} -\frac{1}{4} -\frac{5}{8}$

$\frac{14}{12} -\frac{2}{8} -\frac{10}{16} =\frac{56-12-30}{48}=\frac{14}{48}=\frac{7}{24}$