Question

doy corona por favor ​

Answer 1

Respuesta:

$\frac{12}{5}$

Explicación paso a paso:

$\left(\frac{\left(1-\frac{1}{6}\right)\left(1-\frac{1}{7}\right)\left(1-\frac{1}{8}\right)}{\left(1+\frac{1}{6}\right)\left(1+\frac{1}{7}\right)\left(1+\frac{1}{8}\right)}\right)^{-1}\\\\\frac{1}{\frac{\left(1-\frac{1}{6}\right)\left(1-\frac{1}{7}\right)\left(1-\frac{1}{8}\right)}{\left(1+\frac{1}{6}\right)\left(1+\frac{1}{7}\right)\left(1+\frac{1}{8}\right)}}\\\\\frac{12}{5}$