Question

Doy corona
me ayudannnn

Answer 1

Respuesta:

Explicación paso a paso:

a) x=10/11 y=13/11

$\left \{ {{5x-3y=1} \atop {2x+y=3}(3)} \right. \\\left \{ {{5x-3y=1} \atop {6x+3y=9}} \right. \\11x=10\\x=\frac{10}{11} \\2(10/11)+y=3\\y=3-\frac{20}{11} \\y=\frac{33}{11}-\frac{20}{11}\\ y=\frac{13}{11}$

b) x=2 y=1

$\left \{ {{-x-2y=-4} \atop {x+y=3}} \right. \\\\-y=-1\\y=1\\x+y=3\\x+1=3\\x=2$

c) x=-1 y=-2

$\left \{ {{x-y=1} \atop {-2x+y=0}} \right. \\-x=1\\x=-1\\x-y=1\\-1-y=1\\y=-1-1\\y=-2$

d) x=2 y=0

$\left \{ {{\frac{1}{2}x+ y=-1}(-1) \atop {x+y=-2}} \right. \\\left \{ {{-\frac{1}{2}x- y=1} \atop {x+y=-2}} \right.\\\frac{1}{2}x=-1\\ x=-2\\x+y=-2\\y=-2+2\\y=0$

e) x=1/4 y=1

$\left \{ {{8x-3y=-1} \atop {4x-y=0}(-2)} \right.\\ \left \{ {{8x-3y=-1} \atop {-8x+2y=0}} \right.\\\\-y=-1\\y=1\\4x-y=0\\4x-1=0\\4x=1\\x=1/4$

f)x=-1/3 y=1/3

$\left \{ {{x-2y=-1}(2) \atop {-2x+y=1}} \right.\\ \left \{ {{2x-4y=-2} \atop {-2x+y=1}} \right.\\\\-3y=-1\\y=1/3\\x-2(1/3)=-1\\x=-1+2/3\\x=-1/3$