Question

doy corona ayúdeme es urgente por favor es para hoy
:(

Answer 1

Respuesta:

En la imagen ya están las respuestas directamente.

Explicación paso a paso:

1)

$\sqrt{2}Sen(45)=\sqrt{2}(\frac{\sqrt{2} }{2}) \\\\\sqrt{2}Sen(45)=\frac{2 }{2} \\\\\sqrt{2}Sen(45)=1$

Falso

$4Sen^{2}(60)=4(\frac{\sqrt{3} }{2} )^{2}\\\\4Sen^{2}(60)=4(\frac{3}{4} )\\\\4Sen^{2}(60)=3$

Verdadero

$Tan(30)Cot(60)=(\frac{\sqrt{3} }{3} )(\frac{\sqrt{3} }{3} )\\\\Tan(30)Cot(60)=\frac{3}{9}\\\\Tan(30)Cot(60)=\frac{1}{3}$

Falso

$(Sec(45)\times Cot(30))^{2}=(\sqrt{2}\times \sqrt{3} )^{2}\\(Sec(45)\times Cot(30))^{2}=(2)(3)\\(Sec(45)\times Cot(30))^{2}=6$

Falso

2)

$M=(Sec(45)\times Csc(45))^{3Tan(45)}\\\\M=(\sqrt{2}\times \sqrt{2} )^{3(1)}\\M=(2 )^{3}\\M=8$

e) 8

3)

$B=\frac{Tan^{2}(60)+Csc(60)\times Sen(60)}{Tan(45)} \\\\B=\frac{(\sqrt{3} )^{2}+(\frac{2\sqrt{3} }{3})(\frac{\sqrt{3} }{2} )}{1} \\\\B=3+\frac{(2)(3)}{(3)(2)}\\\\B=3+1\\\\B=4$

c) 4

4)

$N=Sec(30)\times Csc(60)-Tan(30)\times Cot(60)\\\\N=(\frac{2\sqrt{3} }{3})(\frac{2\sqrt{3} }{3})-(\frac{\sqrt{3} }{3} )(\frac{\sqrt{3} }{3} )\\\\N=\frac{(4)(3)}{(3)(3)}-\frac{3}{(3)(3)} \\\\N=\frac{4}{3}-\frac{1}{3} \\\\N=\frac{3}{3}\\\\N=1$

b)1

5)

$Tan(30)=\frac{x}{6\sqrt{3} } \\\\x=6\sqrt{3} Tan(30)\\\\x=6\sqrt{3} (\frac{\sqrt{3} }{3} )\\\\x=\frac{(6)(3)}{3} \\\\x=6$

c)6

Suerte!!