Question

Diagonal del rectángulo de base 4,8 cm y altura 3'6cm

Answer 1

Solo hay que usar pitagoras:

${D}^{2} = {4.8}^{2} + {3.6}^{2} \\ {D}^{2} = 23.04 + 12.96 \\ D = \sqrt{36} \\ D = 6$