Determine el volumen ocupado por 5.37 moles de un gas a 215°C y 1.33 atm de presión.
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V P = n R T
R = 0.0821 (atm L / mol K)
t = 215 + 273 = 488 K
P = 1.33 atm
n = 5.,37 mol
v = 5.37 mol x 0.0821 (atm L/ mol K) x 488 K
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1.33 atm
V = 161.76 L
R = 0.0821 (atm L / mol K)
t = 215 + 273 = 488 K
P = 1.33 atm
n = 5.,37 mol
v = 5.37 mol x 0.0821 (atm L/ mol K) x 488 K
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1.33 atm
V = 161.76 L
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