Question

Determine el area en m2 de un rombo cuya diagonal menor es 10m y su diagonal mayor es 24m

Answer 1

Diagonal mayor = 24m
Diagonal menor = 10m
Area del rombo = diagonal mayor por diagonal menor /2
A = D*d/2
A = 24m * 10m/2
A = 240m²/2
A = 120m²
Area del rombo es = 120m²

Answer 2

$Area \ del \ Rombo = \frac{Diagonal Mayor * diagonal menor}{2} \\ \\ Area \ del \ Rombo = \frac{24\ m * 10\ m}{2} \\ \\ Area \ del \ Rombo = \frac{240m^2}{2} \\ \\ \boxed{Area \ del \ Rombo = 120\ m^2}$

Espero que te sirva, salu2!!!!