Determinar la presion de atm de 170 g de NH3 el cual ocupa un volumen de 5lt a 77°C (N=14)
a)45
b)55
c)57,4
d)61
e)75,2 -Necesito la solución.
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P · V = n · R · T
R = 0.0821 (L atm / mol K)
T = 77 ºC + 273 = 350 K
V = 5 L
n (moles) = masa/Mm
Mm NH3 = 17 g/mol
n = 170 g/17 g/mol = 10 moles
P = n · R · T
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V
P = 10 mol · 0.0821 (L atm / mol K) · 350 K
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5 L
P = 57.47 atm RESPUESTA C
R = 0.0821 (L atm / mol K)
T = 77 ºC + 273 = 350 K
V = 5 L
n (moles) = masa/Mm
Mm NH3 = 17 g/mol
n = 170 g/17 g/mol = 10 moles
P = n · R · T
````````````
V
P = 10 mol · 0.0821 (L atm / mol K) · 350 K
````````````````````````````````````````````````````````
5 L
P = 57.47 atm RESPUESTA C
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