determinar la formula empirica y formula molecular de la cafeina si tiene 49.5% masa de C, 5.15% de H, 28.9% de N, y 16.5% de O. La masa molar de este compuesto es alrededor de 195g/mol
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1. calcular moles
C: 49.5 g/ 12 g/mol = 4.125 mol
H: 5.15 g / 1 g/mol = 5.15 mol
N: 28.9 g / 14 g/mol = 2.064 mol
O: 16.5 g / 16 g/mol = 1.031 mol
2. dividir entre el menor de los resultados
C: 4.125 mol / 1.031 mol = 4
H: 5.15 mol / 1.031 mol = 5
N: 2.064 mol = 1.031 mol = 2
O: 1.031 mol / 1.031 mol = 1
3. FE: C4H5N2O
4. Calcular Mm FE
C: 4 x 12 = 48 g/mol
H: 5 x 1 = 5 g/mol
N: 2 x 14 = 28 g/mol
O: 1 x 1 6 = 16 g/mol
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Mm = 97 g/mol
5. calcular n
n = Mm compuesto / Mm FE
n = 195 g/mol / 97 g/mol
n = 2
6. FM: (C4H5N2O)2 = C8H10N4O2
mol /
C: 49.5 g/ 12 g/mol = 4.125 mol
H: 5.15 g / 1 g/mol = 5.15 mol
N: 28.9 g / 14 g/mol = 2.064 mol
O: 16.5 g / 16 g/mol = 1.031 mol
2. dividir entre el menor de los resultados
C: 4.125 mol / 1.031 mol = 4
H: 5.15 mol / 1.031 mol = 5
N: 2.064 mol = 1.031 mol = 2
O: 1.031 mol / 1.031 mol = 1
3. FE: C4H5N2O
4. Calcular Mm FE
C: 4 x 12 = 48 g/mol
H: 5 x 1 = 5 g/mol
N: 2 x 14 = 28 g/mol
O: 1 x 1 6 = 16 g/mol
``````````````````````````````
Mm = 97 g/mol
5. calcular n
n = Mm compuesto / Mm FE
n = 195 g/mol / 97 g/mol
n = 2
6. FM: (C4H5N2O)2 = C8H10N4O2
mol /
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