Question

Determinar la derivada

Answer 1

Respuesta:

Explicación paso a paso:

7)  $y = f(x) = 4x^{-\frac{2}{5} }$

    $y' = f'(x) = 4.(-\frac{2}{5} ).x^{-\frac{2}{5}-1 }$

    $y' = f'(x) = -\frac{8}{5}.x^{-\frac{7}{5} }$

    $y' = f'(x) = -\frac{8}{5x^{\frac{7}{5} }}$

    $y' = f'(x) = -\frac{8}{5\sqrt[5]{x^{7} } }} = -\frac{8}{5x\sqrt[5]{x^{2} } }}$

7)  $y = f(x) = 5x^{-\frac{8}{3} }$

    $y' = f'(x) = 5.(-\frac{8}{3} ).x^{-\frac{8}{3}-1 }$

    $y' = f'(x) = -\frac{40}{3}.x^{-\frac{11}{3} }$

    $y' = f'(x) = -\frac{40}{3x^{\frac{11}{3} }}= -\frac{40}{3\sqrt[3]{x^{11} } }$

    $y' = f'(x) = -\frac{40}{3x^{3}\sqrt[3]{x^{2} } }$