Question

Determinar la composición centesimal de glucosa

Answer 1

Respuesta:

C = 12 x 6 = 72

H = 1 x 12 = 12

O = 16 x 6 = 96

Peso molecular: 180 g/mol.

C = 72 ÷ 180 = 0.4 x 100 = 40%

H = 12 ÷ 180 = 0.06 x 100 = 6%

O = 96 ÷ 180 = 0.53 x 100 = 53%