determinar el vertice de cada parabola
b(x)=-5x2
f(x)=-2x+1/3x2
f(x)=x2+x+1
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Ecuación de parábola:
ax² + bx + c
Vértice:
x = -b / 2a
y = f(x), el "x" es el encontrado anteriormente!
b(x) = -5x²
x = -b / 2a = - 0 / 2(5) = 0
y = 5(0)² = 0
v = (0,0)
f(x) = -2x + (1/3)x²
f(x) = (1/3)x² - 2x
x = -b / 2a = - (-2) / 2(1/3) = 2/ (2/3) = 3
y = (1/3)(3)² - 2(3) = 3 - 6 = -3
v = (3, -3)
f(x) = x² + x + 1
x = -b / 2a = - 1 / 2(1) = - 1/2
y = ( -1/2 )² + ( -1/2) + 1
y = 1/4 - 1/2 + 1 = 3/4
v = ( -1/2, 3/4 )
Espero haberte ayudado, saludos!
ax² + bx + c
Vértice:
x = -b / 2a
y = f(x), el "x" es el encontrado anteriormente!
b(x) = -5x²
x = -b / 2a = - 0 / 2(5) = 0
y = 5(0)² = 0
v = (0,0)
f(x) = -2x + (1/3)x²
f(x) = (1/3)x² - 2x
x = -b / 2a = - (-2) / 2(1/3) = 2/ (2/3) = 3
y = (1/3)(3)² - 2(3) = 3 - 6 = -3
v = (3, -3)
f(x) = x² + x + 1
x = -b / 2a = - 1 / 2(1) = - 1/2
y = ( -1/2 )² + ( -1/2) + 1
y = 1/4 - 1/2 + 1 = 3/4
v = ( -1/2, 3/4 )
Espero haberte ayudado, saludos!
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