Question

Determinar el valor de N
(32.53)2.34
N =
(3.516​

Answer 1

Respuesta:

Explicación paso a paso:

T = 3,14159 26535 89793 23846 2643..

e = 2,71828 18284 59045 23536 0287.. . = lim

( >

1 f k

n

n-roî

= base de los logaritmos naturales

fi = 1,41421 35623 73095 0488. . .

fi = 1,‘73205 08075 68877 2935.. .

\/5 = 2,23606 79774 99789 6964...

$2 = 1,25992 1050.. .

b = 1,44224 9570. . .

@ = lJ4869 8355.. .

z = 1,24573 0940. . .

er = 23,14069 26327 79269 006. . .

~9 = 22,46915 77183 61045 47342 715.. .

ec = 15,X426 22414 79264 190.. .

log,, 2 = 0,30102 99956 63981 19521 37389. . .

log,, 3 = 0,47712 12547 19662 43729 60279. . .

log,, e = 0,43429 44819 03251 82765. . .

log,, ?r = 0,49714 98726 94133 85435 12683...

log, 10 = In 10 = 2,30258 50929 94046 68401 7991.. .

log, 2 = In 2 = 0.69314 71805 59946 30941 72

Answer 2

Respuesta:

(32.53) 2.34 N =  (3.516​)

(32.53) · 2.34N = 3.516

(32.53) · 2.34N = 76.1202

$\frac{32.53\cdot \:2.34N}{76.1202}=\frac{3.516}{76.1202}$

$N=\frac{3.516}{76.1202}$

Saludos...