determina las raíces de la siguiente ecuación ecuación cuadrática
aplicando la formula cuadrática , la respuesta de la ecuación
porfa!! es urgente depende mi vida de esto y GRACIAS!!!!! c:
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Resolver.
x² - 5x + 6 = 0 Factorizas Trinomio de la forma x² + bx + c
(x - 3)(x - 2) = 0 Tiene 2 raices reales
x - 3 = 0
x = 3
o
x - 2 = 0
x = 2
Solucion
(3 , 2)
Por formula.
A = 1
b = - 5
c = 6
x = [ - b ±√(b² - 4ac)]/2a
x = [ - (-5) ± √((-5)² - 4(1)(6)] /2(1)
x = [ 5 ± √ (25 - 24)] /2
x = [5 ±√1]/2
x = (5 ± 1)/2
x1 = ( 5 +1)/2
x1 = 6/2
x1 = 3
x2 = (5 - 1)/2
x2 = 4/2
x2 = 2
Solucion.
(3 , 2)
3x² - 2x - 5 = 0
a = 3
b = - 2
c = - 5
x = [ - (- 2)±√((-2)² -4(3)(-5))] /2(3)
x = [ + 2 ± √(4 + 60)] /6
x = [ 2 ±√64]/ 6
x = [ 2 ± 8)/6
x1 = ( 2 +8)/6
x1 = 10/6 Simplificamos
x1 = 5/3
x2 = (2 - 8)/6
x2 = -6/6
x2 = -1
Solucion
(5/3 , - 1)
x² - 5x + 6 = 0 Factorizas Trinomio de la forma x² + bx + c
(x - 3)(x - 2) = 0 Tiene 2 raices reales
x - 3 = 0
x = 3
o
x - 2 = 0
x = 2
Solucion
(3 , 2)
Por formula.
A = 1
b = - 5
c = 6
x = [ - b ±√(b² - 4ac)]/2a
x = [ - (-5) ± √((-5)² - 4(1)(6)] /2(1)
x = [ 5 ± √ (25 - 24)] /2
x = [5 ±√1]/2
x = (5 ± 1)/2
x1 = ( 5 +1)/2
x1 = 6/2
x1 = 3
x2 = (5 - 1)/2
x2 = 4/2
x2 = 2
Solucion.
(3 , 2)
3x² - 2x - 5 = 0
a = 3
b = - 2
c = - 5
x = [ - (- 2)±√((-2)² -4(3)(-5))] /2(3)
x = [ + 2 ± √(4 + 60)] /6
x = [ 2 ±√64]/ 6
x = [ 2 ± 8)/6
x1 = ( 2 +8)/6
x1 = 10/6 Simplificamos
x1 = 5/3
x2 = (2 - 8)/6
x2 = -6/6
x2 = -1
Solucion
(5/3 , - 1)
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