Question

despeje de fórmul
$3 + \frac{3}{ \sqrt{x} } - y = 3 = > x$


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Answer 1

Respuesta:

x=9/y²

Explicación:

$3 + \frac{3}{\sqrt{x} } - y = 3 \\\\\frac{3}{\sqrt x}=3-3+y\\\\\frac{3}{\sqrt x}=y\\\\\sqrt x(\frac{3}{\sqrt x})=\sqrt x(y)\\\\3=y\sqrt x\\\\\frac{3}{y}=\sqrt x \\\\(\frac{3}{y})^{2} =(\sqrt x)^2\\\\\frac{9}{y^2}=x$