Question

desarrollo la expresión (3p+4q)³ utilizando el teorema binomial ​

Answer 1

Explicación paso a paso:

(3p+4q)³= (3p+4q) x (3p+4q) x (3p+4q)

(3p+4q) x (3p+4q) = 9p^2 + 24pq + 16q^2

(9p^2 + 24pq + 16q^2) x (3p+4q)

= 27p^3 + 72p^2q + 48pq^2 + 36p^2q + 96pq^2+64q^3

=27p^3 + 109p^2q + 144 pq^2 + 64q^3

Answer 2

Respuesta:

$(3p)^{3} + 3*(3p)^{2} * (4q)^{2} + (4q)^{3} \\27p^{3} + 3 * 9p^{2} * 4q + 3 * 3p*16q^{2} +64q^{3} \\27p^{3} + 108p^{2} q +144pq^{2} +64q^{3}$

Explicación paso a paso: