Question

desarrolla o resuelve los productos:
(u-4)(u+7)=
(x-10)(x-2)=
(3x+2)(3x+6)=
(4a-3)(4a+10)=
(x5+4)(x5-6)=
Ayuda xf

Answer 1

1.=(u)(u)+(u)(7)+(−4)(u)+(−4)(7)

=u^2+7u−4u−28

=u^2+3u−28

2.=(x)(x)+(x)(−2)+(−10)(x)+(−10)(−2)

=x^2−2x−10x+20

=x^2−12x+20

3.=(3x)(3x)+(3x)(6)+(2)(3x)+(2)(6)

=9x^2+18x+6x+12

=9x^2+24x+12

4.=(4a)(4a)+(4a)(10)+(−3)(4a)+(−3)(10)

=16a^2+40a−12a−30

=16a^2+28a−30

5.=(x^5)(x^5)+(x^5)(−6)+(4)(x^5)+(4)(−6)

=x^10−6x^5+4x^5−24

=x^10−2x^5−24