Question

derivar

y=arcsen (2x)

Answer 1

Aplica la formula de derivacion correspondiente a arc sen v que es: 

d/dx [arc sen v] = ( dv/dx)/ raiz de [1-v^2] 

Para tu caso v=2/x 

Entonces tienes 

d/dx [arc sen (2/x)] = d/dx(2/x) / raiz de [1-(2/x)^2] 

d/dx [arc sen (2/x)] = -2/(x^2) / raiz de [1-(2/x)^2] 

simplificando esto te da 

d/dx [arc sen (2/x)] = - 2 / [x raiz de ( x^2 - 4)]